diff --git a/exercises/solution/exercise-basic/injection2pniproblem.hh b/exercises/solution/exercise-basic/injection2pniproblem.hh
index 6c45f8d2c1064df24dbef107744b365adbf55855..d0356eb988e0bbd04cd6060cc35af3fba1f59804 100644
--- a/exercises/solution/exercise-basic/injection2pniproblem.hh
+++ b/exercises/solution/exercise-basic/injection2pniproblem.hh
@@ -140,9 +140,9 @@ public:
         NumEqVector values(0.0);
 
         // if we are inside the injection zone set inflow Neumann boundary conditions
-        if (time_ < injectionDuration_
-            && globalPos[1] < 15 + eps_ && globalPos[1] > 7 - eps_ && globalPos[0] > 0.9*this->gridGeometry().bBoxMax()[0])
+         if (injectionActive() && onInjectionBoundary(globalPos))
         {
+        
             // inject nitrogen. negative values mean injection
             // units kg/(s*m^2)
             values[Indices::conti0EqIdx + FluidSystem::N2Idx] = -1e-4;
@@ -193,6 +193,18 @@ public:
     //! set the time for the time dependent boundary conditions (called from main)
     void setTime(Scalar time)
     { time_ = time; }
+    
+    //! Return true if the injection is currently active
+    bool injectionActive() const
+    { return time_ < injectionDuration_; }
+
+    //! Return true if the given position is in the injection boundary region
+    bool onInjectionBoundary(const GlobalPosition& globalPos) const
+    {
+        return globalPos[1] < 15. + eps_
+            && globalPos[1] > 7. - eps_
+            && globalPos[0] > this->gridGeometry().bBoxMax()[0] - eps_;
+    }
 
 private:
     static constexpr Scalar eps_ = 1e-6;
diff --git a/exercises/solution/exercise-basic/params.input b/exercises/solution/exercise-basic/params.input
index 6b1b2d2b4e7818e4ed15c507d863e065f741cd79..c60e5c2d6e6d633ed4811d2473742562ce5282a7 100644
--- a/exercises/solution/exercise-basic/params.input
+++ b/exercises/solution/exercise-basic/params.input
@@ -3,7 +3,6 @@ DtInitial = 3600 # in seconds
 TEnd = 3.154e9 # in seconds, i.e ten years
 
 [Grid]
-LowerLeft = 0 0
 UpperRight = 60 40
 Cells = 24 16