From 19f2c89fefae28ba0e9f8e37c1dfe9ad92d5c8f4 Mon Sep 17 00:00:00 2001
From: melaniel <melanie.lipp@iws.uni-stuttgart.de>
Date: Thu, 13 Feb 2020 09:07:20 +0100
Subject: [PATCH] [example][freeflowchannel] Stokes not Navier Stokes.
---
examples/freeflowchannel/README.md | 2 +-
examples/freeflowchannel/doc/intro.md | 2 +-
2 files changed, 2 insertions(+), 2 deletions(-)
diff --git a/examples/freeflowchannel/README.md b/examples/freeflowchannel/README.md
index eb948e3b31..e1c739d58f 100644
--- a/examples/freeflowchannel/README.md
+++ b/examples/freeflowchannel/README.md
@@ -10,7 +10,7 @@ This example contains a stationary free flow of a fluid through two parallel sol
## Model description
The Stokes model without gravitation and without sources or sinks for a stationary, incompressible, laminar, single phase, one-component, isothermal ($`T=10^\circ C`$) flow is considered assuming a Newtonian fluid of constant density $` \varrho = 1~\frac{\text{kg}}{\text{m}^3} `$ and constant kinematic viscosity $` \nu = 1~\frac{\text{m}^2}{\text{s}} `$. The momentum balance
```math
-\nabla \cdot (\varrho\boldsymbol{u} \boldsymbol{u}^{\text{T}}) - \nabla\cdot\left(\mu\left(\nabla\boldsymbol{u}+\nabla\boldsymbol{u}^{\text{T}}\right)\right)+ \nabla p = 0
+- \nabla\cdot\left(\mu\left(\nabla\boldsymbol{u}+\nabla\boldsymbol{u}^{\text{T}}\right)\right)+ \nabla p = 0
```
with density $`\varrho`$, velocity $`\boldsymbol{u}`$, dynamic viscosity $`\mu=\varrho\nu`$ and pressure $`p`$ and the mass balance
```math
diff --git a/examples/freeflowchannel/doc/intro.md b/examples/freeflowchannel/doc/intro.md
index 7c60c0742b..682e9dab3d 100644
--- a/examples/freeflowchannel/doc/intro.md
+++ b/examples/freeflowchannel/doc/intro.md
@@ -10,7 +10,7 @@ This example contains a stationary free flow of a fluid through two parallel sol
## Model description
The Stokes model without gravitation and without sources or sinks for a stationary, incompressible, laminar, single phase, one-component, isothermal ($`T=10^\circ C`$) flow is considered assuming a Newtonian fluid of constant density $` \varrho = 1~\frac{\text{kg}}{\text{m}^3} `$ and constant kinematic viscosity $` \nu = 1~\frac{\text{m}^2}{\text{s}} `$. The momentum balance
```math
-\nabla \cdot (\varrho\boldsymbol{u} \boldsymbol{u}^{\text{T}}) - \nabla\cdot\left(\mu\left(\nabla\boldsymbol{u}+\nabla\boldsymbol{u}^{\text{T}}\right)\right)+ \nabla p = 0
+- \nabla\cdot\left(\mu\left(\nabla\boldsymbol{u}+\nabla\boldsymbol{u}^{\text{T}}\right)\right)+ \nabla p = 0
```
with density $`\varrho`$, velocity $`\boldsymbol{u}`$, dynamic viscosity $`\mu=\varrho\nu`$ and pressure $`p`$ and the mass balance
```math
--
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